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x^2=30625
We move all terms to the left:
x^2-(30625)=0
a = 1; b = 0; c = -30625;
Δ = b2-4ac
Δ = 02-4·1·(-30625)
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-350}{2*1}=\frac{-350}{2} =-175 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+350}{2*1}=\frac{350}{2} =175 $
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